2730=3x^2+x

Solution for 2730=3x^2+x equation:

2730=3x^2+x

We move all terms to the left:

2730-(3x^2+x)=0

We get rid of parentheses

-3x^2-x+2730=0

We add all the numbers together, and all the variables

-3x^2-1x+2730=0

a = -3; b = -1; c = +2730;
Δ = b2-4ac
Δ = -12-4·(-3)·2730
Δ = 32761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{32761}=181$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-181}{2*-3}=\frac{-180}{-6}
=+30
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+181}{2*-3}=\frac{182}{-6}
=-30+1/3
$